Polynomial Arithmetic and Closure
A polynomial is a sum of terms like \(a\cdot x^n\), where the degree of each term is a whole number and its coefficient is any real number. You add, subtract, and multiply polynomials by combining like terms and distributing, and the result is always another polynomial — closure.
By the end you'll be able to add, subtract, and multiply polynomials by combining like terms and distributing, and explain why the result is always another polynomial.
Predict: the \(x^2\) coefficient of \((x^2+3x)+(2x^2-x)\). Combine to check.
Sort each polynomial's terms into their degree columns, then combine matching-degree coefficients into the result row. Switch to Distribute to see a product expand into a polynomial instead — same idea, one extra step.
\((x^2 + 3x) + (2x^2 - x) = \) \(3x^2 + 2x\)
Polynomials add, subtract, and multiply just like the numbers you already know how to combine — match up the right pieces (same degree for add/subtract, every pair for multiply) and the answer is always another polynomial.
Think of each term as a labeled pile: an "\(x^2\) pile," an "\(x\) pile," a "constant pile." Adding or subtracting two polynomials just merges matching piles — you never mix an \(x^2\) pile with an \(x\) pile, the same way you wouldn't add 3 apples and 2 oranges and call it "5 apple-oranges." Multiplying is different: every term in the first polynomial has to visit every term in the second, so a small polynomial times a small polynomial can produce a much longer one before it's sorted back into piles.
For addition and subtraction, only coefficients of matching-degree terms combine — \(a x^n + b x^n = (a+b)x^n\) — because different powers of \(x\) can't merge. For multiplication, distribute every term of the first factor over every term of the second and combine like terms afterward; since \(x^m \cdot x^n = x^{m+n}\), multiplying a degree-\(m\) polynomial by a degree-\(n\) polynomial always yields a degree-\((m+n)\) result. None of these three operations can ever produce a negative or fractional exponent, so the polynomials are closed under addition, subtraction, and multiplication — unlike division, where \(p(x) \div q(x)\) need not be a polynomial at all.
To add or subtract: line up like terms (distribute a leading minus sign across every term first if you're subtracting), then combine each column's coefficients. To multiply: distribute every term of the first polynomial across every term of the second, then gather the products by degree and combine like terms — exactly what the board above does, one column at a time.
Let \(p(x) = 3x^2 - 2x + 5\) and \(q(x) = -x^2 + 4x - 6\).
Sum: \((3-1)x^2 + (-2+4)x + (5-6) = 2x^2 + 2x - 1\).
Difference: distribute the minus sign first: \(3x^2-2x+5+x^2-4x+6 =
4x^2-6x+11\).
Product: distribute each term of \(p(x)\) across \(q(x)\): \(3x^2(-x^2+4x-6) =
-3x^4+12x^3-18x^2\); \(-2x(-x^2+4x-6) = 2x^3-8x^2+12x\); \(5(-x^2+4x-6) =
-5x^2+20x-30\). Add the columns: \(-3x^4+14x^3-31x^2+32x-30\).
Let \(p(x) = x^2 + 5x - 3\) and \(q(x) = 2x^2 - x + 4\). Find \(p(x) - q(x)\). Distribute the minus sign first: \(x^2+5x-3-2x^2+x-4\). Now combine like terms: \((1-2)x^2 + (5+1)x + (-3-4) = \) ____
Reveal the answer
\((1-2)x^2 + (5+1)x + (-3-4) = \) \(-x^2 + 6x - 7\). Set A's x² coeff = 1, A's x coeff = 5, B's x² coeff = 2, B's x coeff = -1 on the board above, choose Subtract, and check the result row.
More info — why multiplying never breaks closure
Every term you distribute in a product is of the form \(a x^m \cdot b x^n = ab \cdot x^{m+n}\). Since \(m\) and \(n\) are whole numbers (degrees of polynomial terms), their sum \(m+n\) is also a whole number — there's no way distributing and combining like terms can hand you a negative or fractional exponent. That's the same reason \(x^2 \cdot x^3 = x^5\), never \(x^{2/3}\) or \(x^{-1}\). See the Math is Fun link in Dive deeper for more on why the product of two polynomials is always a polynomial.
Check your understanding
Subtract: \((x^3 + 2x^2 - x) - (x^3 - 3x^2 + 5)\).
Which of these could NEVER be the result of adding, subtracting, or multiplying two polynomials?
Expand \((x+3)^2\) as a product of polynomials: \((x+3)(x+3)\). What's the result?
Multiply: \((x-2)(x^2+3x-1)\).
Recap
- A polynomial is a sum of terms \(a\cdot x^n\) with whole-number exponents; its degree is the largest exponent with a nonzero coefficient.
- Add/subtract: combine like terms — only coefficients of matching-degree terms combine. Distribute a leading minus sign across every term before subtracting.
- Multiply: distribute every term of the first factor over every term of the second, then combine like terms; a degree-\(m\) times a degree-\(n\) polynomial gives a degree-\((m+n)\) result.
- Closure: adding, subtracting, or multiplying two polynomials always produces another polynomial — never a negative or fractional exponent. Division is the exception.
Dive deeper
- Khan Academy — Adding and subtracting polynomials Practice combining like terms across worked sums and differences.
- Purplemath — Polynomial multiplication Distribute every term when multiplying polynomials.
- Math is Fun — Multiplying Polynomials See why exponents add and the product stays a polynomial.
Sources
- Polynomial Arithmetic and Closure